Use hash or case-statement in Ruby?


Often, when we need to get a value based on the other one, we're using a case-statement. Like this


def realizing_trade_type(realizable_trade_type)

  case realizable_trade_type

  when 'buy'

    'sell'

  when 'short'

    'cover'

  when 'buy_contract'

    'sell_contract'

  when 'short_contract'

    'cover_contract'

  end

end

But, if the conditions and the results are simple values, why don't we use hash for this? We can :)


REALIZING_TRADE_TYPES = {

  'buy'            => 'sell',

  'short'          => 'cover',

  'buy_contract'   => 'sell_contract',

  'short_contract' => 'cover_contract'

}.freeze

Here is the benchmark of both options, executed 10000000 times. It shows that a hash is faster in times for such the kind of usage.


>> require 'benchmark'

true

>> Benchmark.bm(15) do |x|

  x.report('hash') { 10_000_000.times { REALIZING_TRADE_TYPES['buy'] } }

  x.report('case-statement') { 10_000_000.times { realizing_trade_type 'buy' } }

  x.report('empty') { 10_000_000.times {} }

end

                      user     system      total        real

hash              0.990423   0.003412   0.993835 (  1.057612)

case-statement    1.752263   0.004531   1.756794 (  1.762030)

empty             0.380810   0.000728   0.381538 (  0.382153)

So, it's better to use a hash when you are just retrieving some values (like in the example above). If there is additional logic to execute, a case-statement is still a way to go.


Dmitry
Voronov

Full-Stack Developer at JetRockets

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